Increasing order of magnetic moment among the following species is:
$N a^{+}, F e^{+ 3}, C o^{+ 2}, C r^{+ 2}$

N a^{+} < C o^{2 +} < C r^{2 +} < F e^{3 +}

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N a^{+} < F e^{3 +} < C r^{2 +} < C o^{2 +}

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C r^{2 +} < C o^{2 +} < N a^{+} < F e^{3 +}

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C o^{2 +} < N a^{+} < C r^{2 +} < F e^{3 +}

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Solution

The correct option is D $N a^{+} < C o^{2 +} < C r^{2 +} < F e^{3 +}$
Magnetic moment is $μ = \sqrt{n (n + 2)}$ , where n is no. of unpaired electron so more no. of unpaired electron means more magnetic moment.

$N a^{+}$ has zero unpaired electron
$C o^{2 +}$ has 3 unpaired electrons
$C r^{2 +}$ has 4 unpaired electrons
$F e^{3 +}$ has 5 unpaired electron

The order is $N a^{+} < C o^{2 +} < C r^{2 +} < F e^{3 +}$ .

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