Increasing order of oxidation state of metal in
$K M n O_{4}, M n C l_{2}, M n O_{2}, M n (O H)_{3}$ is :

M n (O H)_{3} < M n C l_{2} < M n O_{2} < K M n O_{4}

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K M n O_{4} < M n (O H)_{3} < M n O_{2} < M n C l_{2}

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M n C l_{2} < M n (O H)_{3} < K M n O_{4} < M n O_{2}

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M n C l_{2} < M n (O H)_{3} < M n O_{2} < K M n O_{4}

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Solution

The correct option is D $M n C l_{2} < M n (O H)_{3} < M n O_{2} < K M n O_{4}$
$K M n O_{4}$ $O . N$ of $M n = + 7$
$M n C l_{2}$ $O . N$ of $M n = + 2$
$M n O_{2}$ $O . N$ of $M n = + 4$
$M n (O H)_{3}$ $O . N$ of $M n = + 3$

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