Increasing order of sizes of hybrid orbitals is:

s p, s p^{2}, s p^{3}

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s p^{3}, s p^{2}, s p

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s p^{2}, s p^{3}, s p

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s p^{2}, s p, s p^{3}

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Solution

The correct option is A $s p, s p^{2}, s p^{3}$
As the $p$ charecter increases, the size of the hybrid orbital increases. So the increasing order of the size of hybrid orbital is $s p < s p^{2} < s p^{3}$ . Hence, option A is correct.

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s p, s p^{2} a n d s p^{3}

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N O_{3}^{-}, N O_{2}^{+} a n d N H_{4}^{+}

s p^{3}, s p^{2}, s p^{2}, s p^{3}, s p^{2}, s p^{2}, s p, a n d s p

Question 03

The types of hybrid orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}$ respectively are expected to be

(a) $s p, s p^{3} a n d s p^{2}$

(b) $s p, s p^{2} a n d s p^{3}$

(d) $s p^{2}, s p^{3} a n d s p$

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