Question

Increasing value of magnetic moment for the given compounds is:
(I) $\left[Fe\right(CN{)}_6{]}^{4-}$
(II) $\left[Fe\right(CN{)}_6{]}^{3-}$
(III) $\left[Cr\right(N{H}_3{)}_6{]}^{3+}$
(IV) $\left[Ni\right(H_{2}O{)}_6{]}^{2+}$

• A. I < II < III < IV
• B. IV < III < II < I
• C. II< III < I < IV
• D. I < II < IV < III

Answer 1

The correct option is D I < II < IV < III

No. of unpaired electrons in:
$\left[Fe\right(CN{)}_6{]}^{4-}$ is 0
$\left[Fe\right(CN{)}_6{]}^{3-}$ is 1
$\left[Ni\right(H_{2}O{)}_6{]}^{2+}$ is 2
$\left[Cr\right(N{H}_3{)}_6{]}^{3+}$ is 3
As the number of unpaired electrons increases, magnetic moment increases.