Question

Indentify the compound from the Haworth projection shown below.

• A. $\alpha$-D-(+)glucopyranose
• B. $\beta$-D-(+)glucopyranose
• C. $\alpha$-D-(+)-glucofuranose
• D. $\beta$-D-(+)-Glucose

Answer 1

The correct option is B $\beta$-D-(+)glucopyranose

The $\alpha$ and $\beta$ forms of glucose can be represented as a six-membered ring called pyanose, resembling the organic compound pyran. The position of $OH$ group at anomeric carbon determines whether it is $\alpha$ or $\beta$ glucopyranose where alpha stands for down OH group and beta for up OH group. Hence, the correct answer is option (b).