The correct option is B Saturday
25 June 1983 = 1982 years + Period from 01/01/1983 to 25/06/1983
1600 years have 0 odd days.
300 years have 1 odd days.
Now, 82 years comprise of 20 leap years and 62 ordinary years.
So, the number of odd days in 82 years = 20 2 + 62 = 102 days = 14 weeks and 4 odd days.
In 1983(a non-leap year), till 25th June, the number of odd days is calculated as follows:
Month Jan Feb Mar Apr May Jun
Days 31 + 28 + 31 + 30 + 31 + 25 = 176 days or 25 weeks and 1 odd days
So, total number of odd days = 0 + 1 + 4 + 1 = 6 odd days.
Hence, the day on 25th June 1985 is Saturday (Counting 6 days from Monday).