Indicate in given reaction which one is oxidised or reduced if any :

$H_{2} S O_{3} + 2 H_{2} S ⟶ 3 S + 3 H_{2} O$

H_{2} S

gets oxidised.

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H_{2} S O_{3}

gets reduced.

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Both of these

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None of these

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Solution

The correct option is C Both of these
The oxidation number of S (in $H_{2} S$ ) increases from -2 to 0 (in S). Thus, $H_{2} S$ is oxidized.

The oxidation number of S (in $H_{2} S O_{3}$ ) decreases from +4 to 0 (in S). Thus, $H_{2} S O_{3}$ is reduced.

Suggest Corrections

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