2I−+H2O2→2OH−+I2.
Oxidising agent- H2O2 The oxidation number of O decreases from -1 to -2. Thus, O itself is reduced.
Reducing agent- I−. The oxidation number of I increases from -1 to 0. Thus, I itself is oxidised.
Note:
Any species that is oxidised acts as reducing agent.
Any species that is reduced acts as oxidising agent.