Indicator diagram of an ideal gas is as shown in figure. Find the workdone by the gas in the process ABCD.
A
3000J
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B
3800J
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C
2200J
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D
2400J
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Solution
The correct option is C2200J Work done by the gas in the process ABCD is WABCD=WAB+WBC+WCD Area under process ABWAB=4×105(1×10−3−3×10−3) = −800J Area under process BC,WBC=0 Area under process CDWCD=6×105(6×10−3−1×10−3) =3000J ∴ Net workdone WABCD=2200J