Individual homozygous ab genes were crossed with wild type (++) in Drosophila. The F1 hybrid produced were test crossed. The progenies produced were:
++ = 900
ab = 600
+a = 115
+b = 105
Calculate the recombination frequency for a and b genes:
A
10MU
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
11MU
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
12MU
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
13MU
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D 13MU Number of recombinants
= 115 + 105 = 220
Total number of progenies
= 900 + 600 + 115 + 105 = 1720
Recombination frequency (RF)
= (Total No. of recombinants / Total No. of progeny) 🗙100