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Mendel's Law of Inheritance

Individual ho...

Question

Individual homozygous for cd genes were crossed with wild type ++. The $F_{1}$ dihybrid, thus produced was test crossed. It produced progeny in the following ratio ++ 900; +d115; cd 880; c + 105. What is the distance between c and d genes?

47 units

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88 units

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11 units

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5.75 units

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Solution

The correct option is C 11 units
The distance between c and d genes = ( Recombinants / Total individuals ) x 100
Total individuals = 2000
Recombinants = 220
= ( 220 / 2000 ) x 100
= 22 / 2
= 11
So correct answer is ' C '.

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