Question

Industrially, $H_2{O}_2$ is obtained by the following cyclic process :
$\begin{array}{c}2-Ethylanthraquinol\\ \left(P\right)\end{array}\stackrel{O_2}{\underset{H_2/Pd}{\rightleftharpoons }}\begin{array}{c}2-Ethylanthraquinone\\ \left(Q\right)\end{array}+H_2{O}_2$
Which one of the following properties is wrong about the mixture of organic solvents in which the reaction is carried out?

• A. It must resist oxidation.
• B. It must be miscible with water.
• C. It must dissolve both (P) and (Q).
• D. It is generally a mixture of ester and hydrocarbon.

Answer 1

The correct option is B It must be miscible with water.

Industrially $H-{20}_2$ is obtained by this reaction

$2$ ethylanthraquinol $\frac{o_2}{H_2/pd}2-$ ethylanthraquinone

It is auto-oxidation of $2$- alkylanthraquints. The wrong statement is that, organic solvents should be miscible with water because it dissolves just like that, means the organic solvent wouldn't be miscible in water.