If the linear density of the rod of length L starting from one end (x=0) varies as λ=A+bx, then its centre of mass of the rod will be at
You are given a rod of length 'L'. The linear mass density varies as λ′. λ=a+bx. Here a & b are constants and the mass of the rod increases as x increases. Find the mass of the rod.
The linear charge density of a thin metallic rod varies with the distance ′x′ from one end as λ=λ0x2(0⩽x⩽l). The total charge on the rod is: