Question

Initial concentration of reactant for $n$th order reaction is '$a$'. Which of the following relations is correct about $t_{1/2}$ of the reaction?

• A. $\ln t_{1/2}=\ln \left(constant\right)-(n-1){\log }_{e}a$
• B. $\ln t_{1/2}=\ln n+\ln \left(constant\right)-\ln a$
• C. $t_{1/2}\ln n=\ln \left(constant\right)+\ln a_0$
• D. $\ln t_{1/2}=n\ln a_0$

Answer 1

The correct option is A $\ln t_{1/2}=\ln \left(constant\right)-(n-1){\log }_{e}a$

$t_{1/2}\propto \frac{1}{a^{n-1}}$
$t_{1/2}=k\frac{1}{a^{n-1}}$
$\ln t_{1/2}=\ln k-(n-1){\log }_{e}a$