Question

Initial concentration of the reactant is 1 M .. the concentration becomes 0.9 0.8 0.7 in 2 hr ,4 hr, 6 hr respectively then order of the reaction

Ans is 0 pls put it on the paper

Answer 1

A zeroth-order reaction is one whose rate is independent of concentration; its differential rate law is rate = k. We refer to these reactions as zeroth order because we could also write their rate in a form such that the exponent of the reactant in the rate law is 0:

rate=−Δ[A]/Δt
=k[reactant]^0
=k(1)
=k
so,here in first case rate =(1-0.9)/2=0.05

In second case rate=(1-0.7)/6=0.05

In third case rate=(1-0.8)/4=0.05
So given example is of zero order reaction.