Initial volume of a gas is 1 L at temperature 100 K. What is the volume of a gas at 300 K.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 3
Given
$V_{1} = 1 L; T_{1} = 100 K; T_{2} = 300 K; V_{2} = ?$
We know, $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}} \Rightarrow V_{2} = \frac{V_{1} T_{2}}{T_{1}}$
$∴ V_{2} = \frac{1 \times 300}{100} = 3$

Suggest Corrections

Similar questions

Q. The volume of a gas is directly proportional to its absolute temperature. If the temperature of a gas is raised from

300 K

600 K

, and its volume at

300 K

3.0 L

, what is its volume at

600 K

Q. Gas at

300

K is compressed to reduced its volume to half of it's volume, At what temperature will it become double of it's initial volume?

Q. The value of gas is directly proportional to its absolute temperature. If the temperature of a gas is raised from 300 K to 600 K, and its volume at 300 K is 3.0 L. What is its volume at 600 K?

If the temperature of a gas is increased by 1 K at constant pressure, its volume increases by 0.0035 of the initial volume. The temperature of the gas is :

Q. The work done when

2 m o l e s

of an ideal gas is compressed from a volume of

5 m^{3}

1 d m^{3}

at an initial temperature of

300 K

, under a pressure of

100 k P a

is:

Join BYJU'S Learning Program

Initial volume of a gas is 1 L at temperature 100 K. What is the volume of a gas at 300 K.

The correct option is C 3Given V1=1L;T1=100K;T2=300K;V2=?We know, V1T1=V2T2⇒V2=V1T2T1∴V2=1×300100=3

The correct option is C 3
Given
$V_{1} = 1 L; T_{1} = 100 K; T_{2} = 300 K; V_{2} = ?$
We know, $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}} \Rightarrow V_{2} = \frac{V_{1} T_{2}}{T_{1}}$
$∴ V_{2} = \frac{1 \times 300}{100} = 3$