Question

Initially, a gas is present at $2$ atm pressure. If the temperature of the gas is doubled keeping amount of gas and volume constant, then the percentage increase in pressure will be:

• A. $50\%$
• B. $40\%$
• C. $100\%$
• D. $80\%$

Answer 1

Answer: (C)

$100\%$

$P\propto T\Rightarrow \frac{P_1}{T_1}=\frac{P_2}{T_2}$

$\Rightarrow \frac{2}{T}=\frac{P}{2T}\Rightarrow P_2=4atm$

Percentage increase= $\frac{(4-2)}{2}\times 100=100$%