Question

Initially, an ideal gas has a pressure of 6 atmospheres and a temperature of 27${}^o$C in a closed inflexible container. What will be new pressure of the gas, if the temperature is decreased to $-{73}^o$C ?

• A. 2 atm
• B. 3 atm
• C. 4 atm
• D. 8 atm
• E. 9 atm

Answer 1

The correct option is C 4 atm

Here given gas is ideal and container is closed fixed ,This means volume of container is constant we have to find new pressure at -${73}^{0}C$ .So it's always good to use ideal gas equation PV = nRT Where P = Pressure of gas at given condition

V = Volume of given container, n = No. of moles of given gas present in container, R = Universal gas constant , T = Temperature at given condition

now using above equation as $\frac{P_1}{T_1}=\frac{P_2}{T_2}$ Where we have given $P_1=6$ atm, $T_1=$ 300 Kelvin, $T_2=$ 200 Kelvin $P_2$= ?

solving above equation $P_2=$ 4 atm