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Question

Initially both blocks are at rest on a horizontal surface and string is just tight. At t=0, two constant horizontal forces F1 and F2 start acting on blocks as shown. f1 and f2 are friction forces acting on 10 kg and 20 kg block (coefficient of friction between blocks and ground are 0.5). Values of F1 and F2 are given in column - I. Then match magnitudes of f1, f2 and direction of f1 with corresponding values of F1 and F2 given in column - II [g=10 m/s2].



ColumnIColumnII(A)F2=120 N, F1=40 N(p)f2=100 N, f1=20 N(B)F2=160 N, F1=40 N(q)f2=20 N, f1=50 N(C)F2=60 N, F1=90 N(r)f2=70 N, f1=50 N(D)F2=20 N, F1=90 N(s)unit vector in direction of f1 is ^i(t)unit vector in direction of f1 is ^i

A
A-p,s; B-p,t; C-q,s; D-q,s
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B
A-p,s; B-p,s; C-q,t; D-q,s
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C
A-p,s; B-p,t; C-q,s; D-r,s
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D
A-p,s; B-p,t; C-q,t; D-q,t
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Solution

The correct option is A A-p,s; B-p,t; C-q,s; D-q,s
As in all the conditions:
|F1+F2|<|f1|max+|f2|max
So, both blocks wont move in any case.
|f1|max=50 N and |f2|max=100 N
To understand each situation, make first F.B.D of that block on which External force is exceeding friction force as additional force will be provided by tension and then FBD of other block.
Option A:

Option B:

Option C:

Option D:
So,
A B C D
p,s p,t q,s q,s

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