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Standard XII

Chemistry

Characteristics of Equilibrium Constant

Initially mol...

Question

Initially mole of $P {C l}_{5}$ and $0.2$ mole of $P {C l}_{3}$ are mixed in one litre vessel. At equilibrium $0.4$ mole of $P {C l}_{3}$ is present. The value of $K c$ for the reaction $P {C l}_{5 (g)}$ $\Leftrightarrow$ $P {C l}_{3 (g)}$ is:

0.13

molL

^{- 1}

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0.05

molL

^{- 1}

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0.065

molL

^{- 1}

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0.1

molL

^{- 1}

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Solution

The correct option is B $0.05$ molL $^{- 1}$
${P C l}_{5} ⇌ {P C l}_{3}$
$1$ $0.2$ initial
$0.8$ $0.4$ equilibrium
$K_{C} = \frac{[0.4]}{[0.8]} = 0.05 {m o l L}^{- 1}$

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Similar questions

Q. Initially

0.8 m o l e

P C l_{5}

and

0.2 m o l e

P C l_{3}

are mixed in one litre vessel. At equilibrium

0.4 m o l e

P C l_{3}

is present .

The value of

K_{c}

for the reaction

P C l_{5 (g)} ⟺ P C l_{3 (g)} + C l_{2} (g)

Q. Consider the zero order reaction

R \to P

Starting with 4 moles of R in a one litre container, after half an hour only 1 mole of R is left unreacted. The value of k for the reaction is:

Q. A quantity of

P C l_{5}

was heated in a 10 litre vessel at

250^{\circ} C

P C l_{5 (g)} ⇌ P C l_{3 (g)} + C l_{2 (g)}

.
At equilibrium, the vessel contains 0.1 mole of

P C l_{5}

, 0.2 mole of

P C l_{3}

and 0.2 mole of

C l_{2}

. The equilibrium constant is :

Q. A quantity of

P C l_{5}

was heated in a 10 litre vessel as

250^{o} C; P C l_{5 (g)} ⇌ P C l_{3 (g)} + C l_{2 (g)}

. At equilibrium the vessel contains 0.1 mole of

P C l_{5}

. 0.20 mole of

P C l_{3}

and 0.2 mole of

C l_{2}

. The equilibrium constant of the reaction is:

Q. In the reaction

P C l_{5} (g) \Leftrightarrow P C l_{3} (g) + C l_{2} (g)

the equilibrium concentration of

P C l_{5}

and

P C l_{3}

are 0.4 and 0.2 mole/litre respectively. If the value of

K_{C}

is 0.5 what is concentration of

C l_{2}

in moles/litre ?

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Initially mole of PCl5 and 0.2 mole of PCl3 are mixed in one litre vessel. At equilibrium 0.4 mole of PCl3 is present. The value of Kc for the reaction PCl5(g)⇔ PCl3(g) is:

The correct option is B 0.05 molL −1PCl5⇌PCl3 1 0.2 initial 0.8 0.4 equilibriumKC=[0.4][0.8]=0.05molL−1

Initially mole of $P {C l}_{5}$ and $0.2$ mole of $P {C l}_{3}$ are mixed in one litre vessel. At equilibrium $0.4$ mole of $P {C l}_{3}$ is present. The value of $K c$ for the reaction $P {C l}_{5 (g)}$ $\Leftrightarrow$ $P {C l}_{3 (g)}$ is:

The correct option is B $0.05$ molL $^{- 1}$
${P C l}_{5} ⇌ {P C l}_{3}$
$1$ $0.2$ initial
$0.8$ $0.4$ equilibrium
$K_{C} = \frac{[0.4]}{[0.8]} = 0.05 {m o l L}^{- 1}$