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Initially swi...

Question

Initially switch S was open and capacitors \(C\), \(2C\) were having charges \(Q\) and \(2Q\) respectively as shown in figure. Find charge flown in the direction 1 shown in figure after switch \(S\) is closed

A

(\frac{2 Q}{5})

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B

(- \frac{2 Q}{5})

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C

(\frac{4 Q}{5})

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D

(- \frac{4 Q}{5})

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Solution

The correct option is C $(\frac{4 Q}{5})$

$\frac{Q - Q_{1}}{C} - \frac{Q_{1}}{C} + \frac{(2 Q - Q_{1})}{2 C} = 0$
$2 Q - 4 Q_{1} + 2 Q - Q_{1} = 0$
$Q_{1} = \frac{4 Q}{5}$

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