Question

Initially, the switch is in position 1 for a long time and then shifted to position 2 at $t=0$ as shown in figure. Just after closing switch, the magnitude of current through the capacitor is :

• A. zero
• B. $\frac{E}{2R}$
• C. $\frac{E}{R}$
• D. None of these

Answer 1

The correct option is C $\frac{E}{R}$

just before $t=0$
Switch Position 1
Steady state, hence $i_o=\frac{E}{R}$
Switch Position 2
The presence of inductor does not let the current change instantaneously.
$L\frac{di}{dt}+\frac{i}{C}dt-iR=0$
So, at t=0, current in closed loop (confiding of capacitor) will remain same.