Initially the switch is open, the left plate is given a total charge $+ Q$ , and the right plate is kept neutral, now after closing the switch, find out the charge flown through the switch.

Q / 2

from plate to earth

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Q / 2

from earth to plate

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Q

from plate to earth

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Q

from earth to plate

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Solution

The correct option is C $Q$ from plate to earth
When switch is closed, charge on its outer plate will become zero. So according to Gauss law, charge on outer surface of the left plate will aslo become zero.
Since left plate is isolated, total charge $+ Q$ will appear on its inner plate.

On the right plate, initial charge was zero, After closing the switch, charge on it is $- Q$ . It means $Q$ amount of charge has flown from plate to earth.

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Initially the switch is open, the left plate is given a total charge +Q, and the right plate is kept neutral, now after closing the switch, find out the charge flown through the switch.

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