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Byju's Answer
Standard XIII
Physics
V-I Characteristics of a Transistor
Input charact...
Question
Input characterstics of a CE configuration is graph between
I
B
and
V
B
E
keeping
V
C
E
as constant.
A
True
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B
False
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Solution
The correct option is
A
True
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Similar questions
Q.
Draw the typical input and output characteristics of an n-p-n transistor in CE configuration. Show how these characteristics can be used to determine (a) the input resistance
(
r
i
)
, and (b) current amplification factor
β
.
Input charcteristics: It is the graph drawn between input current and input voltage when output voltage is kept constant.
Output characteristics : It is the graph drawn between output current and output voltage when input current is kept constant.
(a) Input resitance
(
R
i
=
[
Change in emitter base voltage
(
△
V
B
E
)
Change in base current
(
△
I
B
)
]
at constant
V
C
E
or
R
i
=
(
△
V
B
E
△
I
B
)
V
C
E
(b) Current amplification factor,
(
β
)
=
(
△
I
C
△
I
B
)
V
C
E
=
△
I
C
△
I
E
−
△
I
C
=
△
I
C
△
I
E
△
I
C
△
I
E
−
△
I
C
△
I
E
=
α
1
−
α
⇒
β
=
α
1
−
α
Q.
In output characterstics graph as value of
I
B
E
increases, the value of
I
C
E
also increases.
Q.
Output characteristics of an
n
−
p
−
n
transistor in
C
E
configuration is shown in the figure. Determine:
(i) dynamic output resistance
(ii) dc current gain and
(iii) ac current gain at an operating point
V
C
E
=
10
V
, when
I
B
=
30
μ
A
.
Q.
Draw the typical input and output characteristics of an n-p-n transistor in CE configuration. Show how these characteristics can be used to determine (a) the input resistance
(
r
i
)
, and (b) current amplification factor
β
.
Input charcteristics: It is the graph drawn between input current and input voltage when output voltage is kept constant.
Output characteristics : It is the graph drawn between output current and output voltage when input current is kept constant.
(a) Input resitance
(
R
i
=
[
Change in emitter base voltage
(
△
V
B
E
)
Change in base current
(
△
I
B
)
]
at constant
V
C
E
or
R
i
=
(
△
V
B
E
△
I
B
)
V
C
E
(b) Current amplification factor,
(
β
)
=
(
△
I
C
△
I
B
)
V
C
E
=
△
I
C
△
I
E
−
△
I
C
=
△
I
C
△
I
E
△
I
C
△
I
E
−
△
I
C
△
I
E
=
α
1
−
α
⇒
β
=
α
1
−
α
Q.
In the circuit shown in the figure, the input voltage
V
i
is
20
V
,
V
B
E
=
0
V
and
V
C
E
=
0
V
. The value of
I
B
is given by
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