Insert $4$ arithmetic means between $3$ and $23$ .

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Solution

First term is $t_{1} = a = 3$
Sixth term is $t_{6} = a + 5 d = 23$
$d = 4$

The other four terms are $t_{2} = a + d = 3 + 4 = 7$
$t_{3} = a + 2 d = 3 + 2 * 4 = 11$
$t_{4} = a + 3 d = 3 + 3 * 4 = 15$
$t_{5} = a + 4 d = 3 + 4 * 4 = 19$

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