$I n s e r t f o u r g e o m e t r i c m e a n s b e t w e e n 160 a n d 54$

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Solution

$160, 160 r, {160 r}^{2}, {160 r}^{3}, {160 r}^{4}$
$a = 160$
${160 r}^{5} = 5$
$r^{5} = \frac{5}{160} = \frac{1}{31} = \frac{1}{2^{5}} = \sqrt[5]{\frac{1}{2^{5}}} = \frac{1}{2}$
$∴ 160, 80, 40, 20, 10, 5.$

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