wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Insert three numbers 1 and 256 so that the resulting sequence is a G.P.

A
0,16,64
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4,0,64
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4,6,64
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4,16,64
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 4,16,64
Let, g1,g2,g3 be three numbers between 1 and 256

1,g1,g2,g3,256 are in G.P

First term a=1

5th term =256

ar4=256

(1)r4=256

r4=44

r=4

Now, g1=ar=1×4=4

g2=ar2=1×42=16

g3=ar3=1×43=64

The required numbers are 4,16,64

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Venn Diagrams
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon