Insert two arithmetic means between $11$ and $17$ .

13

and

15

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

11

and

13

No worries! We‘ve got your back. Try BYJU‘S free classes today!

13

and

14

No worries! We‘ve got your back. Try BYJU‘S free classes today!

11

and

15

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $13$ and $15$
Given:
$a = 11, b = 17$ and $n = 2$
The common difference for inserting arithmetic means are calculated as $d = \frac{17 - 11}{2 + 1} = 2$
Using the above value of $d$ , the two arithmetic means will be,
$A_{1} = 11 + 2 = 13$
$A_{2} = 11 + 2 (2) = 15$
So, the two numbers are $13$ and $15$ .

Suggest Corrections

Similar questions

Q. Insert

4

arithmetic means between

11

and

26

Q. Mean of

14, 17, 11, 13, 26, 21, 31

, and

19

Insert one arithmetic mean between 3 and 13.

Prove that:
(i) $\frac{1}{3 + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{3}} + \frac{1}{\sqrt{3} + 1} = 1$
(ii) $\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{6}} + \frac{1}{\sqrt{6} + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{8}} + \frac{1}{\sqrt{8} + \sqrt{9}} = 2$

The marks of

20

students in a test were as follows:

5, 6, 8, 9, 10, 11, 11, 12, 13, 13, 14, 14, 15, 15, 15, 16, 16, 18, 19, 20.

The mean is

Join BYJU'S Learning Program

Insert two arithmetic means between 11 and 17.

The correct option is A 13 and 15Given:a=11,b=17 and n=2The common difference for inserting arithmetic means are calculated as d=17−112+1=2Using the above value of d, the two arithmetic means will be,A1=11+2=13A2=11+2(2)=15So, the two numbers are 13 and 15.

Insert two arithmetic means between $11$ and $17$ .