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Standard X

Physics

Magnetic Field Due to a Straight Current Carrying Conductor

Inside a long...

Question

Inside a long straight cylindrical wire, there is a long round cylindrical cavity whose axis is parallel to the axis of the wire and displaced from the latter by a distance l. A direct current density J flows along the wire. Find the magnetic induction inside the cavity. What will be the magnetic induction at $l = 0$ ?

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Solution

Assume that uniform current flows in the cavity superposed on actual current.
$\to B = \frac{μ_{0}}{2} \to J \times (A P - P C) = \frac{μ_{0}}{2} \to J \times l$
if $l = 0, B = 0$ .

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Assume that uniform current flows in the cavity superposed on actual current.→B=μ02→J×(AP−PC)=μ02→J×lif l=0,B=0.

Assume that uniform current flows in the cavity superposed on actual current.
$\to B = \frac{μ_{0}}{2} \to J \times (A P - P C) = \frac{μ_{0}}{2} \to J \times l$
if $l = 0, B = 0$ .