Inside a smooth circular tube of radius 5m, a small ball. A moves at speed 10 m/s and strikes another ball B of double the mass located at diametrically opposite point if coefficient of restitution is 0.5, the time when 2nd collision occurs is $\frac{n π}{2}$ sell. find n.

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Solution

Speed of the balls of masses m and 2m after collision are 0 and 5 m/s.
$t = \frac{π 5}{10} + \frac{2 π 5}{5} = \frac{π}{2} + 2 π = \frac{5 π}{2}$

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