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Question

10tan1(1x+x2)dx= ___
  1. In 2
  2. π4
  3. π2
  4. π2In2


Solution

The correct option is A In 2
10tan1(1x+x2)dx=10(π2tan1(x+(1x)1x(1x)))dx=π210(tan1(1x)+tan1x)dxπ2210tan1(x)dx=ln 2

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