The correct option is A 20
The value of the given definite integral is
I=∫10π0|sinx|dx
=10∫π0|sinx|dx
[∵|sinx|] is periodic with period π)
=10∫π0sinx dx
[∵sinx>0 in interval (0,π)]
This can be further simplified as
I=20∫π20sinx dx
[∵sin(π−x)=sinx]
=20[−cosx]π20=20