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Question

20x[x2+42]dx= where [.] or the greatest integer function

A
4
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B
5
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C
3
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D
6
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Solution

The correct option is B 5
20x[x2+42]dx =20x[x22+2]dx
20x{[x22]+2}dx
=20x.0dx+22x.1dx+4 ....(xϵ[0,2)[x22]=0 and xϵ[2,2)[x22]=1
(x21)22+4=(21)+4=5
Ans: B

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