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∫_0^2t e^-t ...

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∫_0^2t e^{-t} dt =?

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Q. The value of the integral

\int_{0}^{2} \frac{t}{t + i} d t

A = \int_{0}^{1} \frac{e^{t}}{1 + t} d t

\int_{0}^{1} e^{t} l n (1 + t) d t =

g (x) = x \int 1 e^{t^{2}}

d t

then the value of

h (x) = x^{3} \int 3 e^{t^{2}} d t

\int_{0}^{1} \frac{e^{t} d t}{1 + t} = A

then the value of

\int_{0}^{1} \frac{e^{t} d t}{(1 + t)^{2}}

1 \int 0 \frac{e^{t} d t}{1 + t} =

A then the value of

1 \int 0 \frac{e^{t} d t}{{(1 + t)}^{2}}

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