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Byju's Answer
Standard XII
Mathematics
Trigonometric Ratios of Multiples of an Angle
∫04π cos2014 ...
Question
∫
4
π
0
c
o
s
2014
x
d
x
is equal to
A
4.2013.2011.2009.........3.1
2014.2012.2010.......4.2
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B
2.2013.2011.2009.........3.1.
π
2014.2012.2010........6.4
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C
4.1013.2011.2009.......3.1.
π
2014.2012.2010..........6.4
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D
8.2013.2011.2009........3.1
2014.2012.2010...........4.2
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Solution
The correct option is
D
2.2013.2011.2009.........3.1.
π
2014.2012.2010........6.4
∫
4
π
0
c
o
s
2014
x
d
x
=
8
∫
π
2
0
c
o
s
2014
x
d
x
=
8
×
(
2013
2014
)
(
2011
2012
)
(
2009
2010
)
.
.
.
.
.
.
.
(
3
4
)
(
1
2
)
⋅
π
2
=
2.2013.2011.2009.......3.1.
π
2014.2012.2010......6.4
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