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Question

4π0cos2014xdx is equal to

A
4.2013.2011.2009.........3.12014.2012.2010.......4.2
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B
2.2013.2011.2009.........3.1.π2014.2012.2010........6.4
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C
4.1013.2011.2009.......3.1.π2014.2012.2010..........6.4
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D
8.2013.2011.2009........3.12014.2012.2010...........4.2
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Solution

The correct option is D 2.2013.2011.2009.........3.1.π2014.2012.2010........6.4
4π0cos2014xdx
=8π20cos2014xdx
=8×(20132014)(20112012)(20092010).......(34)(12)π2
=2.2013.2011.2009.......3.1.π2014.2012.2010......6.4

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