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Question

π/40cos2x dx=1k. Find k

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Solution

π/40cos2xdx=1k
Let 2x=p.2dx=dp
as xπ4
2xπ2
as x0
2x0
=12π/20cospdp=12sinp]π/20
=12[10]=12
Now 1k=12
k=2

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