Question

${\int }_0^1(e^x+x^2)dx$ is equal to

• A. $e-1$
• B. $e+1$
• C. $e-\frac{2}{3}$
• D. $e+\frac{2}{3}$

Answer 1

The correct option is C $e-\frac{2}{3}$

${\int }_0^1(e^x+x^2)dx$
$={\int }_0^1{e}^{x}dx+{\int }_0^1{x}^{2}dx$
$=e^x{|{}_0^1+\frac{x^2}{3}|}_0^1=(e-1)+(\frac{1}{3}-0)$
$=e-\frac{2}{3}$