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Question

(1+2x+3x2+4x3+...)dx=

A
(1+x)1+c
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B
(1x)1+c
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C
(1x)11+c
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D
None of these
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Solution

The correct option is B (1x)1+c
(1+2x+3x2+4x3+..)dx
=(1x)2dx[(1x)2=1+2x+3x2]
=dx(1x)2
=(1x)1+c
(1+2x+3x2+.....)dx=(1x)1+c


















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