Question

$\int (7y^5+6y^2-1)=\frac{7y^6}{6}+b{y}^3-y$.Find $b$

Answer 1

$\int (7y^5+6y^2-1)dy$

$=7\left(\frac{y^6}{6}\right)+6\left(\frac{y^3}{3}\right)-y+c$

$=\frac{7y^6}{6}+2y^3-y+c$

$bycomparison,b=2$