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Byju's Answer
Standard XII
Mathematics
Standard Formulae - 1
∫-aasin6x+sin...
Question
∫
a
−
a
(
s
i
n
6
x
+
s
i
n
7
x
)
d
x
is equal to
A
2
∫
a
0
s
i
n
6
x
d
x
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B
2
∫
a
0
s
i
n
7
x
d
x
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C
2
∫
a
0
(
s
i
n
6
x
+
s
i
n
7
x
)
d
x
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D
zero
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Solution
The correct option is
A
2
∫
a
0
s
i
n
6
x
d
x
I
=
∫
a
−
a
s
i
n
6
x
d
x
+
∫
a
−
a
s
i
n
7
x
d
x
⇒
s
i
n
6
x
is even function
s
i
n
7
x
is odd function
I
=
2
∫
a
0
s
i
n
6
x
d
x
+
0
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0
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