$\int \frac{f^{'} (x)}{f (x)} d x = log [f (x)] + c$

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Solution

Let $f (x) = t$

Differentiate on both sides ;

$\Rightarrow f^{^{'}} (x) d x = d t$

Integral becomes : $\frac{d t}{t} = l o g [t] + c$

$= l o g [f (x)] + c$

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