1+lnx=t2(1x)dx=2tdt∴I=∫(2tdt√t2)=2∫dt=2t+C=2√1+lnx+C∴m=2
Find the integral of the given function w.r.t - x
y=x−1x+1x2
∫ex(x−1)(x−ln x)x2dx is equal to