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Question

cosx+xsinxx(x+cosx)dx=?

A
logx+cosxx+c
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B
log|x(x+cosx)|+c
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C
logxx+cosx+c
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D
logx(cosx+xsinx)|+c
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Solution

The correct option is D logxx+cosx+c
cosx+xsinxx(x+cosx)dx

=x+cosxx(1sinx)x(x+cosx)dx

=x+cosxx+sinxx(x+cosx)dx

=(1x)[1sinxx+cosx]dx

=(1x)dx[f(x)f(x)]dx

=f(x)=x+cosx

=ln|x|ln|f(x)|+C

=ln|x|ln|x+cosx|+C

=lnxx+cosx+C
Hence, solved.



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