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Question

dx1+e2x

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Solution

dx1+e2x
=(e2x1+e2x+1)dx
=e2x1+e2xdx+1.dx
=122e2x1+e2xdx+x+c
=12ln1+e2x+x+c
=(12ln1+e2x+x)+c
121+e2xx+c

1112407_1139139_ans_7241941c38b8431fa2d4e24db81bf5a2.jpg

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