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Question

dx2axx2=ansin1[xa1]
The value of n is:

A
0
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B
1
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C
1
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D
none of these
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Solution

The correct option is A 0
LetI=12axx2dx=ansin1[x21]+C........(1)

= 1(x22ax)dx

= 1(x22ax+a2a2)dx

= 1((xa)2a2)dx

1a2(xa)2dx


[1a2x2dx=sin1[xa]+C]



I=sin1[xaa]



I=a0sin1[xa1]+C........(2)

On comparing (1)&(2) we get

an=a0
n=0 Hence correct opton is A

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