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Byju's Answer
Standard XII
Mathematics
Integration by Substitution
∫dxx xn + 1 i...
Question
∫
d
x
x
(
x
n
+
1
)
is equal to
A
1
n
log
(
x
n
x
n
+
1
)
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B
1
n
log
(
x
n
+
1
x
n
)
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C
log
(
x
n
x
n
+
1
)
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D
None of these
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Solution
The correct option is
C
1
n
log
(
x
n
+
1
x
n
)
∫
d
x
x
(
x
n
+
1
)
Expand
∫
1
x
n
+
1
d
x
Substitute
u
=
1
x
n
+
1
→
d
x
=
−
x
n
+
1
n
d
u
Now solving,
=
−
1
n
∫
1
u
d
u
=
−
1
n
log
u
=
−
1
2
log
(
1
x
n
+
1
)
=
1
n
log
(
1
+
x
n
x
n
)
Suggest Corrections
0
Similar questions
Q.
If
x
1
=
1
and
x
n
+
1
=
1
x
n
(
√
1
+
x
2
n
−
1
)
,
n
≥
1
,
n
∈
N
, then
x
n
is equal to :
Q.
[Hint: multiply numerator and denominator by
x
n
− 1
and put
x
n
=
t
]