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Question

dxx(xn+1) is equal to

A
1nlog(xnxn+1)
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B
1nlog(xn+1xn)
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C
log(xnxn+1)
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D
None of these
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Solution

The correct option is C 1nlog(xn+1xn)
dxx(xn+1)
Expand
1xn+1dx
Substitute u=1xn+1dx=xn+1ndu
Now solving,

=1n1udu

=1nlogu=12log(1xn+1)=1nlog(1+xnxn)

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