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Question

dxx(x5+3)

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Solution

I=dxx(x5+3)

I=x4x5(x5+3)dx

Let t=x5
5x4 dx=dt
Therefore,
I=dt5t(t+3)

I=1513[1t1t+3]dt

I=115log|tt+3|+C

I=115log|x5x5+3|+C

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