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Byju's Answer
Standard XII
Mathematics
Special Integrals - 1
∫ e x x x · ...
Question
∫
e
x
x
(
x
⋅
(
log
x
)
2
+
2
log
x
)
d
x
Open in App
Solution
∫
e
x
x
(
x
(
log
x
)
2
+
2
log
x
)
d
x
=
∫
e
x
x
(
x
(
log
x
)
2
+
2
log
x
x
)
d
x
=
∫
e
x
x
(
x
(
log
x
)
2
)
+
∫
e
x
x
2
log
x
x
d
x
=
e
x
(
log
x
)
2
−
∫
e
x
2
log
x
x
d
x
+
∫
e
x
2
log
x
x
d
x
+
C
=
e
x
(
log
x
)
2
+
C
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2
0
log
cos
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d
x
=
π
2
log
(
1
2
)
, then
∫
π
/
2
0
log
sec
x
d
x
=
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