Question

$\int \frac{{\sec }^{2}x}{\tan x}dx=$

Answer 1

Let $\tan x=t$

${\sec }^{2}xdx=dt$

$\int \frac{{\sec }^{2}xdx}{\tan x}=\int \frac{dt}{t}=\ell nt+c=\ell n\left(\tan x\right)+c$