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Question

sin2xcos2x(sin3x+cos3x)2

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Solution

I=sin2xcos2x(sin3x+cos3x)2dx=tan2xsec2x(1+tan2x)2dxPut1+tan3x=tdtdx=3tan2xsec2xNowI=dtt2=13t1+C=13(1+tan2x)+C.

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